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Proof step 46 from proof byte-law-neg (previous step)

0 ≤ i ∧ 127 < i % 256, 0 < i, 0 ≤ i, 127 < i ⊦ i2b(~ i) = i2b(~(i % 256 - 256))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 47:
0 < i % 256, 127 < i, 0 ≤ i, 0 < i, 127 < i % 256 ⊦ i2b(~ i) = i2b(256 - i % 256)

Rule argument

Additional information

Used simplifier rules: i0 ≠ 0, i0 < i ⊦ (* i) < j → (* i0) < j;% ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward)% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)% ⊦ ~(i - j) = j - i;