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Proof step 5 from proof byte-law-neg (previous step)

⊦ i2b(~ i) = i2b(~ b2i(i2b(i))), ¬ i < ~128 ∧ ¬ 127 < i

User applied rule cut formula

And obtained the following new goals

Proof step 6:
i < 0 ⊦ i2b(~ i) = i2b(~ b2i(i2b(i))), ¬ i < ~128 ∧ ¬ 127 < i
Proof step 36:
⊦ i < 0, i2b(~ i) = i2b(~ b2i(i2b(i))), ¬ i < ~128 ∧ ¬ 127 < i

Rule argument

fma: i < 0

Additional information

Used formulas: i < 0