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Proof step 7 from proof byte-law-neg (previous step)

i < ~128, i < 0 ⊦ i2b(~ i) = i2b(~ b2i(i2b(i)))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
⊦ i < 0 ∧ ~128 ≤ i % 256 → b2i(i2b(i)) = i % 256
Proof step 9:
¬(i < 0 ∧ ~128 ≤ i % 256), i < ~128, i < 0 ⊦ i2b(~ i) = i2b(~ b2i(i2b(i)))
Proof step 16:
i < 0 ∧ ~128 ≤ i % 256, i < ~128, i < 0 ⊦ i2b(~ i) = i2b(~(i % 256))

Rule argument

name: bib-neg-high rotate: F subst: [i] → [i]

Additional information

Used terms: i