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Proof step 117 from proof byte-law-righthift-not (previous step)

6 ≠ 0, i2b(bits2uint(true ' + false ' + firstn(6 -1, false ' + false ' + false ' + false ' + false ' + false '))) = i2b(2147483392 + bits2uint(true ' + true ' + false ' + firstn(6 -1, false ' + false ' + false ' + false ' + false ' + false '))) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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