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Proof step 129 from proof byte-law-righthift-not (previous step)

2 ≠ 0, i2b(bits2uint(true ' + false ' + false ' + false ' + false ' + false ' + firstn(2 -1, false ' + false '))) = i2b(2147483392 + bits2uint(true ' + true ' + false ' + false ' + false ' + false ' + false ' + firstn(2 -1, false ' + false '))) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ bits2uint(bits + true ') = bits2uint(bits) * 2 + 1;% ⊦ bits2uint(true ') = 1;% ⊦ bits2uint(bits + false ') = bits2uint(bits) * 2;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ firstn(1, boolvar ' + bits) = boolvar ';