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Proof step 25 from proof byte-law-righthift-not (previous step)

i2b(bits2int(sublist(0, n, int2bits(128)))) = i2b(~1), # int2bits(128) = n + i→n(bits2int(bitsand(int2bits(1), int2bits(31)))), # int2bits(~128) ≤ i→n(bits2int(bitsand(int2bits(1), int2bits(31)))), i→n(bits2int(bitsand(int2bits(1), int2bits(31)))) < # int2bits(128), # int2bits(~128) < # int2bits(128) ⊦ n = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ 0 ≤ i → int2bits(i) = uint2bits(i) subst: [i] → [1] rotate: F spec: int2bits inst: name: int2bits-pos

Additional information

Used terms: 1