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Proof step 36 from proof byte-law-righthift-not (previous step)

i2b(bits2int(sublist(0, n, int2bits(128)))) = i2b(bits2int(sublist(0, n0, int2bits(~128)))), # int2bits(128) = n + i→n(bits2int(bitsand(int2bits(1), int2bits(31)))), # int2bits(~128) = n0 + i→n(bits2int(bitsand(int2bits(1), int2bits(31)))), i→n(bits2int(bitsand(int2bits(1), int2bits(31)))) < # int2bits(128), i→n(bits2int(bitsand(int2bits(1), int2bits(31)))) < # int2bits(~128) ⊦ n = 0, n0 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ 0 ≤ i → int2bits(i) = uint2bits(i) subst: [i] → [1] rotate: F spec: int2bits inst: name: int2bits-pos

Additional information

Used terms: 1