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Proof step 47 from proof byte-law-righthift-not (previous step)

0 ≤ 128, # uint2bits(128) = 1 + n, i2b(bits2int(sublist(0, n, uint2bits(128)))) = i2b(bits2int(true ' + false ' + false ' + false ' + false ' + false ' + false ')) ⊦ n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 48:
i2b(64) = i2b(bits2int(true ' + false ' + false ' + false ' + false ' + false ' + false ')) ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ bits2uint(true ') = 1;% ⊦ bits2uint(bits + false ') = bits2uint(bits) * 2;% ⊦ bits2int(false ' + bits) = bits2uint(bits);% ⊦ bits + [] = bits;% ⊦ sublist(0, 0, bits) = [];%n ≠ 0 ⊦ sublist(0, (* n), boolvar ' + bits) = boolvar ' + sublist(0, n -1, bits);% ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;%n0 < n ⊦ (* n) = m0 + (* n0) ↔ n - n0 = m0;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ # boolvar ' = 0 +1;% ⊦ #(bits + bits0) = # bits + # bits0;% ⊦ bits + boolvar = bits + boolvar ';% ⊦ boolvar + boolvar0 = boolvar ' + boolvar0 ';% ⊦ uint2bits(1) = false + true;%1 < i ⊦ uint2bits((* i)) = uint2bits(i / 2) + (i % 2 = 1);