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Proof step 50 from proof byte-law-righthift-not (previous step)

⊦ i = 128 ∧ j = 1 → i2b (bits2int (sublist(0, # fillsgn(32, int2bits(128)), mklist(false, i→n(bits2int(bitsand(int2bits(1), int2bits(31))))) + fillsgn(32, int2bits(128))))) ≠ i2b (bits2int (sublist(0, # fillsgn(32, int2bits(~128)), mklist(false, i→n(bits2int(bitsand(int2bits(1), int2bits(31))))) + fillsgn(32, int2bits(~128)))))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 51:
i2b (bits2int(sublist(0, # fillsgn(32, int2bits(128)), mklist(false, i→n(bits2int(bitsand(int2bits(1), int2bits(31))))) + fillsgn(32, int2bits(128))))) = i2b (bits2int(sublist(0, # fillsgn(32, int2bits(~128)), mklist(false, i→n(bits2int(bitsand(int2bits(1), int2bits(31))))) + fillsgn(32, int2bits(~128))))) ⊦

Proof step 50 from proof byte-law-righthift-not (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information