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Proof step 68 from proof byte-law-righthift-not (previous step)

¬ # int2bits(128) ≤ 32, i2b(bits2int(sublist(0, # fillsgn(32, int2bits(128)), false ' + fillsgn(32, int2bits(128))))) = i2b(bits2uint(firstn(31, fillsgn(32, int2bits(~128))))), # int2bits(~128) ≤ 32 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ int2bits(j) ≠ [];% ⊦ # bits = 0 ↔ bits = [];% ⊦ m ≤ n ∧ n < n0 → m < n0; (forward)% ⊦ m < n → n ≠ 0; (forward)% ⊦ ¬ m ≤ n ↔ n < m;