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Proof step 82 from proof byte-law-righthift-not (previous step)

32 = n + # int2bits(128), i2b(bits2uint(firstn(31, mklist(false, n) + int2bits(128)))) = i2b(bits2uint(firstn(31, mklist(true, 32 - # int2bits(~128)) + int2bits(~128)))), # int2bits(128) ≤ 32, # int2bits(~128) ≤ 32 ⊦

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 83:
32 = n0 + # int2bits(~128), 32 = n + # int2bits(128), i2b(bits2uint(firstn(31, mklist(false, n) + int2bits(128)))) = i2b(bits2uint(firstn(31, mklist(true, n0) + int2bits(~128)))), # int2bits(128) ≤ 32, # int2bits(~128) ≤ 32 ⊦

Rule argument

seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [32, # int2bits(~128), n0] rotate: T spec: nat inst: name: elim-sub

Additional information

Used simplifier rules: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: 32, # int2bits(~128), n0