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Proof step 7 from proof byte-law-sub-one-01 (previous step)

⊦ i2b(i - j) = i2b(~ b2i(i2b(j + ~ i)))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
⊦ i2b(~ i) = i2b(~ b2i(i2b(i)))

Rule argument

name: byte-law-neg rotate: T subst: [i] → [j + ~ i]

Additional information

Used simplifier rules: ⊦ i + ~ j = i - j;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i;% ⊦ ~(i - j) = j - i; Used terms: j + ~ i