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Proof step 2 from proof byte-law-sub-one (
previous step
)
i - j = i + ~ j ⊦ i2b(i - j) = i2b(b2i(i2b(i)) - j)
User applied rule insert equation
And obtained the following new goals
Proof step 3
:
⊦ i2b(i + ~ j) = i2b(b2i(i2b(i)) - j)
Rule argument
pos: left 1 flags: discard
Additional information