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Proof step 4 from proof byte-length (previous step)

~128 ≤ b2i(by) ∧ b2i(by) ≤ 127, 8 < # int2bits(b2i(by)) ⊦ b2i(by) = ~128

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
8 < # int2bits(b2i(by)), ~128 < b2i(by) ⊦ b2i(by) = ~128

Rule argument

Additional information

Used simplifier rules: byte-le: ⊦ b2i(by) ≤ 127;% ⊦ i ≠ j → (i ≤ j ↔ i < j);