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Proof step 1 from proof byte-min (conclusion)

⊦ b2i(by) ≤ ~128 ↔ b2i(by) = ~128

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: byte-nls: ⊦ ¬ b2i(by) < ~128;% ⊦ i < (* j) ∧ j < 0 → i < 0; (forward)% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i ≠ j → (i ≤ j ↔ i < j);