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Proof step 2 from proof byte-mult-01 (
previous step
)
⊦ i2b(~(i * 256)) = i2b(0)
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 3
:
⊦ ~ i * j = ~(i * j)
Proof step 4
:
⊦ i2b(~ i * 256) = i2b(0)
Rule argument
seq: ⊦ ~ i * j = ~(i * j) subst: [j, i] → [256, i] rotate: T spec: int-mult inst: name: minus-left
Additional information
Used terms: 256, i