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Proof step 2 from proof byte-mult-256-01 (previous step)

~(i * 256 + j) = ~ i * 256 + ~ j ⊦ i2b(~(i * 256 + j)) = i2b(~ j)

User applied rule insert equation

And obtained the following new goals

Proof step 3:
⊦ i2b(~ i * 256 + ~ j) = i2b(~ j)

Rule argument

pos: left 1 flags: discard

Additional information