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Proof step 12 from proof byte-mult-256 (previous step)

j < 0, 0 < i ⊦ i = 0, i2b(i * 256 + j) = i2b(j)

User applied rule cut formula

And obtained the following new goals

Proof step 13:
j % 256 < 0, j < 0, 0 < i ⊦ i = 0, i2b(i * 256 + j) = i2b(j)
Proof step 58:
j < 0, 0 < i ⊦ j % 256 < 0, i = 0, i2b(i * 256 + j) = i2b(j)

Rule argument

fma: j % 256 < 0

Additional information

Used formulas: j % 256 < 0