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Proof step 2 from proof byte-mult-256 (previous step)

⊦ i2b(i * 256 + j) = i2b(j), i = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ 0 ≤ i ∧ 0 ≤ j → i2b(i * 256 + j) = i2b(j)
Proof step 4:
¬(0 ≤ i ∧ 0 ≤ j) ⊦ i2b(i * 256 + j) = i2b(j), i = 0

Rule argument

name: byte-mult-pos rotate: F subst: [j, i] → [j, i]

Additional information

Used terms: j, i