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Proof step 37 from proof byte-mult-256 (previous step)

i0 < 0, 0 < i, ~256 < j0, i0 < i, j0 < 0, i0 * 256 + j0 < 0 ⊦ i = 0, i2b(256 * (i0 + i) + j0) = i2b(j0), i0 + i = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 38:
⊦ i < 0 ∧ j < 0 → i2b(i * 256 + j) = i2b(j)
Proof step 39:
¬(i0 + i < 0 ∧ j0 < 0), i0 < 0, 0 < i, ~256 < j0, i0 < i, j0 < 0, i0 * 256 + j0 < 0 ⊦ i = 0, i2b(256 * (i0 + i) + j0) = i2b(j0), i0 + i = 0

Rule argument

name: byte-mult-neg rotate: F subst: [j, i] → [j0, i0 + i]

Additional information

Used simplifier rules: ⊦ i * j = j * i;% ⊦ i + j = j + i; Used terms: j0, i0 + i