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Proof step 65 from proof byte-mult-256 (previous step)

i < 0, 0 ≤ i0, 0 ≤ j0, j0 < 256 ⊦ i2b(256 * (i0 + i) + j0) = i2b(j0), i = 0, i0 + i = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 66:
⊦ 0 ≤ i ∧ 0 ≤ j → i2b(i * 256 + j) = i2b(j)
Proof step 67:
¬(0 ≤ i0 + i ∧ 0 ≤ j0), i < 0, 0 ≤ i0, 0 ≤ j0, j0 < 256 ⊦ i2b(256 * (i0 + i) + j0) = i2b(j0), i = 0, i0 + i = 0

Rule argument

name: byte-mult-pos rotate: F subst: [j, i] → [j0, i0 + i]

Additional information

Used simplifier rules: ⊦ i * j = j * i;% ⊦ i + j = j + i; Used terms: j0, i0 + i