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Proof step 73 from proof byte-mult-256 (previous step)

i0 + i < 0, j0 < 256, 0 ≤ j0, 0 ≤ i0, i < 0 ⊦ i0 + i = 0, i = 0, i2b((i0 + i + 1) * 256 + (j0 - 256)) = i2b(j0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 74:
⊦ i < 0 ∧ j < 0 → i2b(i * 256 + j) = i2b(j)
Proof step 75:
¬(i0 + i + 1 < 0 ∧ j0 - 256 < 0), i0 + i < 0, j0 < 256, 0 ≤ j0, 0 ≤ i0, i < 0 ⊦ i0 + i = 0, i = 0, i2b((i0 + i + 1) * 256 + (j0 - 256)) = i2b(j0)
Proof step 91:
i0 + i + 1 < 0 ∧ j0 - 256 < 0, i0 + i < 0, j0 < 256, 0 ≤ j0, 0 ≤ i0, i < 0 ⊦ i0 + i = 0, i = 0, i2b(j0 - 256) = i2b(j0)

Rule argument

name: byte-mult-neg rotate: F subst: [j, i] → [j0 - 256, i0 + i + 1]

Additional information

Used terms: j0 - 256, i0 + i + 1