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Proof step 88 from proof byte-mult-256 (previous step)

~256 < i1 ∧ i1 < ~128, i0 + i = ~1, i1 < 0, ~256 ≤ i1, i < 0, 0 ≤ i0 ⊦ i = 0, i1 + 256 = b2i(i2b(i1 + 256))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information