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Proof step 11 from proof byte-mult-neg (previous step)

0 ≤ i * 256 + j, j < 0, i < 0 ⊦ i2b(i * 256 + j) = i2b(j)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ i < 0 ∧ j < 0 → ¬ 0 ≤ i + j subst: [j, i] → [j, i * 256] rotate: F spec: int-abs inst: name: zero-ge-01

Additional information

Used simplifier rules: ⊦ 0 < i → (i * j < 0 ↔ j < 0);% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i < j → (¬ ¬ j ≤ i ↔ false);% ⊦ i * j * j0 = (i * j) * j0;% ⊦ i * j = j * i; Used terms: j, i * 256