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Proof step 9 from proof byte-mult-neg (previous step)

i < 0, j < 0 ⊦ i2b(i * 256 + j) = i2b(j), ¬ 0 ≤ i * 256 + j ∧ ¬ (i * 256 + j) % 256 < ~128, ¬ 0 ≤ i * 256 + j ∧ ¬ ~128 ≤ (i * 256 + j) % 256

User applied rule cut formula

And obtained the following new goals

Proof step 10:
i < 0, j < 0 ⊦ ¬ 0 ≤ i * 256 + j, i2b(i * 256 + j) = i2b(j), ¬ 0 ≤ i * 256 + j ∧ ¬ (i * 256 + j) % 256 < ~128, ¬ 0 ≤ i * 256 + j ∧ ¬ ~128 ≤ (i * 256 + j) % 256

Rule argument

fma: ¬ 0 ≤ i * 256 + j

Additional information

Used simplifier rules: ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i < j → (¬ ¬ j ≤ i ↔ false); Used formulas: ¬ 0 ≤ i * 256 + j