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Proof step 2 from proof byte-nle (previous step)

256 ≤ abs(b2i(by)) ⊦ b2i(by) = 0

User applied rule insert lemma

And obtained the following new goals

Proof step 3:
⊦ ~128 ≤ b2i(by) ∧ b2i(by) ≤ 127
Proof step 4:
~128 ≤ b2i(by) ∧ b2i(by) ≤ 127, 256 ≤ abs(b2i(by)) ⊦ b2i(by) = 0

Rule argument

name: byte-range subst: [by] → [by]

Additional information

Used terms: by