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Proof step 4 from proof byte-nls-02 (previous step)

~128 ≤ b2i(by) ∧ b2i(by) ≤ 127, b2i(by) < 0, 0 ≤ i, 0 < i, i + b2i(by) < 0, 128 ≤ i ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
~128 ≤ b2i(by), b2i(by) < 0, 0 ≤ i, 0 < i, i + b2i(by) < 0, 128 ≤ i ⊦

Rule argument

Additional information

Used simplifier rules: byte-le: ⊦ b2i(by) ≤ 127;% ⊦ i ≤ j ∧ j < j0 → i < j0; (forward)