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Proof step 4 from proof byte-not-max (previous step)

¬ b2i(by) + i ≠ 128 -1, 0 < i, 0 < b2i(by), 126 < b2i(by), b2i(by) + i < 128 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
b2i(by) + i = 127, 126 < b2i(by), 0 < b2i(by), 0 < i ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward)% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;