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Proof step 6 from proof byte-not-max (previous step)

b2i(by) = 127 - i, b2i(by) + i = 127, 126 < b2i(by), 0 < b2i(by), 0 < i ⊦

User applied rule insert equation

And closed the goal!

Rule argument

pos: left 1 flags: discard

Additional information

Used simplifier rules: ⊦ i + (j - i) = j;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i;% ⊦ i < j - i0 ↔ i + i0 < j;% ⊦ i + (* j) < (* j0) ↔ i < j0 - j;% ⊦ i < 1 ↔ i ≤ 0;% ⊦ i < j → (¬ ¬ j ≤ i ↔ false);