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Proof step 8 from proof byte-not-max (previous step)

0 < i, 0 < b2i(by), 126 < b2i(by), b2i(by) + i < 127 ⊦ b2i(by) + i = 127

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
⊦ i < j ↔ i +1 = j ∨ i +1 < j
Proof step 10:
0 < i, 0 < b2i(by), 126 < b2i(by), (b2i(by) + i)+1 = 127 ∨ (b2i(by) + i)+1 < 127 ⊦ b2i(by) + i = 127

Rule argument

seq: ⊦ i < j ↔ i +1 = j ∨ i +1 < j subst: [j, i] → [127, b2i(by) + i] rotate: F spec: int-basic1 inst: name: lsrec

Additional information

Used terms: 127, b2i(by) + i