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Proof step 2 from proof byte-short-neq (previous step)

i2s(i) = i2s(j) ⊦ i2b(i) = i2b(j)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ i2b(i) = i2b(cast(8, i))
Proof step 4:
i2s(i) = i2s(j) ⊦ i2b(cast(8, i)) = i2b(j)

Rule argument

name: byte-is-cast-01 rotate: F subst: [i] → [i]

Additional information

Used terms: i