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Proof step 8 from proof byte-short-neq (previous step)

cast(16, i) = s2i(i2s(j)) ⊦ i2b(cast(8, i)) = i2b(j)

User applied rule cut formula

And obtained the following new goals

Proof step 9:
cast(8, i) = cast(8, cast(16, i)), cast(16, i) = s2i(i2s(j)) ⊦ i2b(cast(8, i)) = i2b(j)
Proof step 18:
cast(16, i) = s2i(i2s(j)) ⊦ cast(8, i) = cast(8, cast(16, i)), i2b(cast(8, i)) = i2b(j)

Rule argument

fma: cast(8, i) = cast(8, cast(16, i))

Additional information

Used formulas: cast(8, i) = cast(8, cast(16, i))