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Proof step 5 from proof byte-sis (previous step)

⊦ i2b(cast(8, cast(16, i))) = i2b(i)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ i2b(i) = i2b(cast(8, i))
Proof step 7:
⊦ i2b(cast(8, cast(16, i))) = i2b(cast(8, i))

Rule argument

name: byte-is-cast-01 rotate: F subst: [i] → [i]

Additional information

Used terms: i