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Proof step 2 from proof byte-unsigned (previous step)

0 ≤ i, 0 < i, i < 256, 128 ≤ i ⊦ i2b(i) = i2b(i - 256)

User applied rule cut formula

And obtained the following new goals

Proof step 3:
0 ≤ i, 0 < i, i < 256, 128 ≤ i ⊦ b2i(i2b(i)) = b2i(i2b(i - 256)), i2b(i) = i2b(i - 256)

Rule argument

fma: b2i(i2b(i)) = b2i(i2b(i - 256))

Additional information

Used simplifier rules: byte-equal: ⊦ b2i(byi) = b2i(byj) ↔ byi = byj; Used formulas: b2i(i2b(i)) = b2i(i2b(i - 256))