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Proof step 8 from proof cast-b2i-01 (
previous step
)
7 ≤ i0, 0 < i0, 0 ≤ i0 ⊦ ¬ 2 ^ i0 ≤ b2i(by), cast(i0 + 1, b2i(by)) = b2i(by), ~1 = i0
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 9
:
0 ≤ i0, 0 < i0, 7 ≤ i0, 2 ^ i0 ≤ b2i(by) ⊦ ~1 = i0, cast(i0 + 1, b2i(by)) = b2i(by)
Rule argument
Additional information