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Proof step 1 from proof cast-b2i (conclusion)

⊦ cast(8, b2i(by)) = b2i(by)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ 8 ≤ i → cast(i, b2i(by)) = b2i(by)

Rule argument

name: cast-b2i-01 rotate: F subst: [by, i] → [by, 8]

Additional information

Used terms: by, 8