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Proof step 21 from proof div-inshort (previous step)

~ ~32768 = 32768, ~ ~32768 < ~(s2i(sho0) / s2i(sho1)), 0 ≤ s2i(sho0), s2i(sho1) < 0, s2i(sho0) / s2i(sho1) < 0, s2i(sho0) / s2i(sho1) < ~32768 ⊦ s2i(sho1) = ~1

User applied rule insert equation

And obtained the following new goals

Rule argument

pos: left 1 flags: discard

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