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Proof step 10 from proof fits-law-band (previous step)

8 < # int2bits(band(b2i(by1), b2i(by2))) ⊦ ¬ 9 ≤ # int2bits(b2i(by1)), band(b2i(by1), b2i(by2)) = cast(8, band(b2i(by1), b2i(by2)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
8 < # int2bits(band(b2i(by1), b2i(by2))), 9 ≤ # int2bits(b2i(by1)) ⊦ band(b2i(by1), b2i(by2)) = cast(8, band(b2i(by1), b2i(by2)))

Rule argument

Additional information

Used simplifier rules: ⊦ int2bits(j) ≠ [];% ⊦ # bits = 0 ↔ bits = [];%0 < n ⊦ (* n) ≤ m → m ≠ 0; (forward)