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Proof step 16 from proof fits-law-bor-01 (previous step)

⊦ s2i(i2s(band(bcompl(s2i(sho1)), bcompl(b2i(by2))))) = band(bcompl(s2i(sho1)), bcompl(b2i(by2))), bcompl(band(bcompl(s2i(sho1)), bcompl(b2i(by2)))) = s2i(i2s(bcompl(band(bcompl(s2i(sho1)), bcompl(b2i(by2)))))), bcompl(b2i(by2)) ∈short

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 17:
⊦ i ∈short ↔ s2i(i2s(i)) = i
Proof step 18:
⊦ s2i(i2s(band(bcompl(s2i(sho1)), bcompl(b2i(by2))))) = band(bcompl(s2i(sho1)), bcompl(b2i(by2))), bcompl(band(bcompl(s2i(sho1)), bcompl(b2i(by2)))) = s2i(i2s(bcompl(band(bcompl(s2i(sho1)), bcompl(b2i(by2)))))), s2i(i2s(bcompl(b2i(by2)))) = bcompl(b2i(by2))

Rule argument

name: inshort-sis rotate: F subst: [i] → [bcompl(b2i(by2))]

Additional information

Used terms: bcompl(b2i(by2))