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Proof step 18 from proof fits-law-bor (previous step)

⊦ b2i(i2b(band(bcompl(b2i(by1)), bcompl(b2i(by2))))) = band(bcompl(b2i(by1)), bcompl(b2i(by2))), bcompl(band(bcompl(b2i(by1)), bcompl(b2i(by2)))) = b2i(i2b(bcompl(band(bcompl(b2i(by1)), bcompl(b2i(by2)))))), b2i(i2b(bcompl(b2i(by2)))) = bcompl(b2i(by2))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 19:
⊦ i ∈byte → b2i(i2b(bcompl(i))) = bcompl(i)

Rule argument

name: bcompl-bib rotate: F subst: [i] → [b2i(by2)]

Additional information

Used simplifier rules: byte2int-in: ⊦ b2i(by) ∈byte; Used terms: b2i(by2)