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Proof step 20 from proof fits-law-bxor-01 (previous step)

¬(bcompl(s2i(sho1)) ∈short ∧ b2i(by2) ∈short), ~32768 ≤ bcompl(b2i(by2)), bcompl(b2i(by2)) ≤ 32767 ⊦ bor(band(s2i(sho1), bcompl(b2i(by2))), band(bcompl(s2i(sho1)), b2i(by2))) = s2i(i2s(bor(band(s2i(sho1), bcompl(b2i(by2))), band(bcompl(s2i(sho1)), b2i(by2))))), s2i(i2s(band(bcompl(s2i(sho1)), b2i(by2)))) = band(bcompl(s2i(sho1)), b2i(by2))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 21:
~32768 ≤ bcompl(b2i(by2)), bcompl(b2i(by2)) ≤ 32767 ⊦ bor(band(s2i(sho1), bcompl(b2i(by2))), band(bcompl(s2i(sho1)), b2i(by2))) = s2i(i2s(bor(band(s2i(sho1), bcompl(b2i(by2))), band(bcompl(s2i(sho1)), b2i(by2))))), s2i(i2s(band(bcompl(s2i(sho1)), b2i(by2)))) = band(bcompl(s2i(sho1)), b2i(by2)), bcompl(s2i(sho1)) ∈short

Rule argument

Additional information

Used simplifier rules: inshort-byte: ⊦ b2i(by) ∈short;