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Proof step 5 from proof fits-law-bxor-01 (previous step)

¬(band(s2i(sho1), bcompl(b2i(by2))) ∈short ∧ band(bcompl(s2i(sho1)), b2i(by2)) ∈short) ⊦ bor(band(s2i(sho1), bcompl(b2i(by2))), band(bcompl(s2i(sho1)), b2i(by2))) = s2i(i2s(bor(band(s2i(sho1), bcompl(b2i(by2))), band(bcompl(s2i(sho1)), b2i(by2)))))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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