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Proof step 5 from proof fits-law-bxor (previous step)

¬(band(b2i(by1), bcompl(b2i(by2))) ∈byte ∧ band(bcompl(b2i(by1)), b2i(by2)) ∈byte) ⊦ bor(band(b2i(by1), bcompl(b2i(by2))), band(bcompl(b2i(by1)), b2i(by2))) = b2i(i2b(bor(band(b2i(by1), bcompl(b2i(by2))), band(bcompl(b2i(by1)), b2i(by2)))))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information