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Proof step 1 from proof fits-law-compl-01 (conclusion)

⊦ bcompl(s2i(sho)) = s2i(i2s(bcompl(s2i(sho))))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ s2i(i2s(i)) = cast(16, i)
Proof step 3:
⊦ bcompl(s2i(sho)) = cast(16, bcompl(s2i(sho)))

Rule argument

name: short-is-cast rotate: F subst: [i] → [bcompl(s2i(sho))]

Additional information

Used terms: bcompl(s2i(sho))