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Proof step 1 from proof fits-law-compl (conclusion)

⊦ bcompl(b2i(by)) = b2i(i2b(bcompl(b2i(by))))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ b2i(i2b(i)) = cast(8, i)
Proof step 3:
⊦ bcompl(b2i(by)) = cast(8, bcompl(b2i(by)))

Rule argument

name: byte-is-cast rotate: F subst: [i] → [bcompl(b2i(by))]

Additional information

Used terms: bcompl(b2i(by))