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Proof step 6 from proof fits-law-compl (previous step)

8 < # int2bits(bcompl(b2i(by))) ⊦ bcompl(b2i(by)) = cast(8, bcompl(b2i(by)))

User applied rule cut formula

And obtained the following new goals

Proof step 7:
8 < # int2bits(bcompl(b2i(by))) ⊦ # int2bits(bcompl(b2i(by))) ≤ # int2bits(b2i(by)), bcompl(b2i(by)) = cast(8, bcompl(b2i(by)))

Rule argument

fma: # int2bits(bcompl(b2i(by))) ≤ # int2bits(b2i(by))

Additional information

Used simplifier rules: byte-bitlength-01: ⊦ 8 < n → ¬ n ≤ # int2bits(b2i(by)); Used formulas: # int2bits(bcompl(b2i(by))) ≤ # int2bits(b2i(by))