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Proof step 11 from proof fits-law-div-stronger (previous step)

~ abs(b2i(by1)) ≤ b2i(by1) / i, b2i(by1) / i < ~128, b2i(by1) / i ≤ abs(b2i(by1)), 0 ≤ abs(b2i(by1)) + b2i(by1) / i, b2i(by1) / i < 0 ⊦ i = ~1, i = 0, b2i(by1) / i = b2i(i2b(b2i(by1) / i))

User applied rule cut formula

And obtained the following new goals

Rule argument

fma: ~ abs(b2i(by1)) < ~128

Additional information

Used simplifier rules: byte-ngr-01: ⊦ ¬ 128 < abs(b2i(by));% ⊦ ~ i < j ↔ 0 < j + i;%i < 0 ⊦ (* i) + j = j - ~ i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i;% ⊦ i < j - i0 ↔ i + i0 < j; Used formulas: ~ abs(b2i(by1)) < ~128