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Proof step 15 from proof fits-law-div-stronger (previous step)

127 < b2i(by1) / i, b2i(by1) / i ≤ abs(b2i(by1)), 0 ≤ abs(b2i(by1)) + b2i(by1) / i, 0 < b2i(by1) / i, 127 < abs(b2i(by1)) ⊦ i = ~1, i = 0, b2i(by1) / i = b2i(i2b(b2i(by1) / i)), b2i(by1) = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ ¬ j < 0 → abs(j) = j subst: [j] → [b2i(by1)] rotate: F spec: int-abs inst: name: Abs-pos

Additional information

Used simplifier rules: byte-gr-127: ⊦ ¬ 127 < b2i(by);% ⊦ ¬ i < j → (i ≠ j ↔ j < i);%j ≠ 0 ⊦ 0 < i → i / j ≤ i; Used terms: b2i(by1)