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Proof step 27 from proof fits-law-div-stronger (previous step)

i ≠ 0, i ≠ 0, 128 / ~ i = 128, b2i(by1) = ~ 128 ⊦ i = 0, i = ~1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 28:
j ≠ 0 ⊦ i / j = i ↔ i = 0 ∨ j = 1

Rule argument

seq: j ≠ 0 ⊦ i / j = i ↔ i = 0 ∨ j = 1 subst: [j, i] → [~ i, 128] rotate: F spec: int-div inst: name: div-eq-same-01

Additional information

Used simplifier rules: ⊦ ~ i = 0 ↔ i = 0;% ⊦ ~ i = j ↔ i + j = 0;% ⊦ (* j) = i0 + (* j0) ↔ j - j0 = i0;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i; Used terms: ~ i, 128