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Proof step 9 from proof fits-law-div (previous step)

¬(~32768 ≤ b2i(by1) / i ∧ b2i(by1) / i ≤ 32767), b2i(by1) / i = b2i(i2b(b2i(by1) / i)) ⊦ i = 0, b2i(by1) / i = s2i(i2s(b2i(by1) / i)), i = ~1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
b2i(by1) / i = b2i(i2b(b2i(by1) / i)) ⊦ i = 0, b2i(by1) / i = s2i(i2s(b2i(by1) / i)), i = ~1, ¬ b2i(by1) / i < ~32768 ∧ ¬ 32767 < b2i(by1) / i

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ i ≤ j ↔ j < i;